Question

Find the sum of the infinte geometric series:

24 + 12 + 6 + 3 + ...

Answer 1

3/2

Answer 2

how

Answer 3

it keeps dividing by 2

Answer 4

or keeps getting cut in half....well half of 3 is 1.5 or 3/2

Answer 5

yes but im not looking for what is next im looking for the sum

Answer 6

wait hold on

Answer 7

you have to use a formula

Answer 8

it says "find the sum" right?

Answer 9

okay...i misunderstood the question apparently

Answer 10

yes find the sum

Answer 11

\[a+ar+ar^2+ar^3+...=\frac{a}{1-r}\] and here
\[a=24,r=\frac{1}{2}\]

Answer 12

sat...would it not be n/2?

Answer 13

so you get
\[\frac{24}{1-\frac{1}{2}}=\frac{24}{\frac{1}{2}}=24\times 2=48\]

Answer 14

yours certainly looks better...i'm goin back to bed

Answer 15

steps clear or no?

Answer 16

yes thanks so much can i ask you another question

Answer 17

a(1-r^n)/(1-r)

Answer 18

derived

Answer 19

sure post away, but make a new thread

Answer 20

becomes

Answer 21

oh u did it already crap

Answer 22

sorry

Answer 23

my connection slow

Answer 24

its ok but thanks anyway :)