x=2y+3z------ solve for y
( i actually tried this one already and had an #epic fail)

Question

jim_thompson5910 · Answer

$$\large x=2y+3z$$


$$\large x-3z=2y$$

$$\large \frac{x-3z}{2}=y$$


$$\large y=\frac{x-3z}{2}$$

If you can, point out where you went wrong.

anonymous · Answer

On the second part!!! im soooo dumb!!!

jim_thompson5910 · Answer

on the second step, I subtracted 3z from both sides because I want to isolate the y term. So I basically want y on one side while everything else is on the other.

jim_thompson5910 · Answer

hopefully that clears things up a bit

anonymous · Answer

Jim im having trouble on # 44...

jim_thompson5910 · Answer

sorry don't know what #44 is, is it posted somewhere on here?

anonymous · Answer

2ab+4=d----solve for a

anonymous · Answer

wana see wat i wrote?

jim_thompson5910 · Answer

sure

anonymous · Answer

2ab+4=d
        -4  -4
2ab/4d
?????????????????? i suck major popsickles

jim_thompson5910 · Answer

You're off to a great start


$$\large 2ab+4=d$$


$$\large 2ab=d-4$$


$$\large a=\frac{d-4}{2b}$$


In the last step I divided both sides by 2b (so the 2 and the b on the left side will cancel out and go away)

anonymous · Answer

Omg,,, i am on problem 60,,,, but im stuck!!! ugh its
 d(a-b)=c-------------- solve for a

jim_thompson5910 · Answer

$$\large d(a-b)=c$$


$$\large a-b=\frac{c}{d}$$


$$\large a=\frac{c}{d}+b$$