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solve for X. log(base3)x^2=2log(base3)4-4log(base3)5
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like this? \[\log_3(x^2) = 2\log_3(4)-4\log_3(5)\]
log_3(x^2)=2log_3(4)-4log_3(5)??????
x^2 = 3^RHS x = sqrt(3^RHS) I think?
x = 0.16
since it is all base three, lets simplify each side down to one log. The left side is already done. On the right side we have: \[2\log_3 (4)-4\log_3(5) = \log_3(4^2)-\log_3(5^4) = \log_3\left(\frac{16}{625}\right)\] So now we have: \[\log_3(x^2) = \log_3\left(\frac{16}{625}\right) \iff x^2 = \frac{16}{625} x = \pm \frac{4}{25}\]
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whoops there should be an arrow in between the fraction 16/625 and x in the last line.
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