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OpenStudy (anonymous):
f(x)=1-3^x
the graph of f is reflected over the line y=x. what is the name of function of the new graph?
15 years ago
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OpenStudy (saifoo.khan):
i think that will be a straight line through which this will be reflected.
15 years ago
OpenStudy (anonymous):
the inverse 0.o
15 years ago
OpenStudy (anonymous):
f¯¹(x)
15 years ago
OpenStudy (saifoo.khan):
i have no idea.
15 years ago
OpenStudy (anonymous):
y = 1-3^x
x = 1-3^y
then solve for y.. I.. don't know how to do that for this problem...
15 years ago
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OpenStudy (anonymous):
you are going to have to use logarithms
15 years ago
OpenStudy (anonymous):
\[ \log_{3}\left| -x+3 \right| =\log_{3}3^y\]\[y=\log_{3}\left| -x+3 \right|\] I think I could be very very wrong lol
15 years ago
OpenStudy (anonymous):
saifoo its add maths funtion
15 years ago
OpenStudy (dumbcow):
\[y = 1 - 3^{x}\]
switch variables
\[x = 1-3^{y}\]
solve for y
\[3^{y} +x = 1\]
\[3^{y} = 1-x\]
\[\log 3^{y} = \log (1-x)\]
\[y*\log 3 = \log(1-x)\]
\[y = \frac{\log (1-x)}{\log 3}\]
15 years ago
OpenStudy (anonymous):
what is the name of function of the new graph?
no name
15 years ago
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OpenStudy (dumbcow):
\[f^{-1}(x)\]
15 years ago
OpenStudy (anonymous):
f(x)\[=1-3^x\]
f(x)=y
\[f(y)^{-1}=x\]
y=1-3^x
1-y=3^x
\[\log_{3}(1-y)=x \]
\[f(y)^{-1}=x\]
\[f(y)^{-1}\]=\[\log_{3}(1-y)\]
if u insert x instead of y
\[f(x)^{-1}\]=\[\log_{3}(1-x)\]
15 years ago
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