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Mathematics 7 Online
OpenStudy (moongazer):

How to solve this?

OpenStudy (moongazer):

3A-B-2C=5 2A+B+3C=6 6A-B+4C=9 solve for 3 unkowns

OpenStudy (moongazer):

Please answer clearly and explain the solution clearly and easy to understand. Thanks! (guaranteed medal for a good answer)

OpenStudy (moongazer):

please show your solutions

OpenStudy (dumbcow):

i would use elimination. btw can you use a graphing calculator

OpenStudy (moongazer):

i don't have a graphing calculator. can you show me eliminating it?

OpenStudy (anonymous):

Can two letters be the same number?

OpenStudy (anonymous):

you have to use partial fractions

OpenStudy (moongazer):

A = 62/27, B =- 25/27, C =-13/27 that is the answer i just don't know how it became that answer

OpenStudy (anonymous):

3(2)-1-2(0) 6-1-0 5-0 5!

OpenStudy (moongazer):

please use the arithmetic method

OpenStudy (anonymous):

what is the arithmetic method?

OpenStudy (moongazer):

i think it the eq. 1 +eq.2

OpenStudy (moongazer):

then so on

OpenStudy (dumbcow):

ok lets eliminate B first Add top 2 equations together 3A -B-2C = 5 2A+B+3C =6 ------------- (i) 5A +C = 11 Next add bottom 2 equations together, this will eliminate B again 2A+B+3C = 6 6A-B+4C = 9 ------------- (ii) 8A +7C = 15 Now solve equations (i) and (ii), lets eliminate C Multiply (i) by -7 Then add (i) and (ii) -35A -7C = -77 8A +7C = 15 ---------------- -27A = -62 A = 62/27 Substitute into (ii) to solve for C 8(62/27) +7C = 15 7C = 15 - (496/27) C = 15/7 - (496/189) C = -91/189 Substitute A and C into one of the original equation to solve for B 2A +B+3C = 6 2(62/27) +B +3(-91/189) = 6 B = 6 + (273/189) -(124/27) B = 539/189

OpenStudy (moongazer):

why is it you have a different answer for B?

OpenStudy (dumbcow):

mine aren't reduced all the way and i prob made a mistake cause working with huge fractions

OpenStudy (dumbcow):

actually i verified it, i think you have a wrong answer for B

OpenStudy (anonymous):

dumbcows answers are correct

OpenStudy (moongazer):

ohh thanks maybe the answer key is wrong ^_^

OpenStudy (dumbcow):

the reduced answer for B is 77/27

OpenStudy (moongazer):

is it ok to subtitute the value of A in 5A +C = 11 to solve for C?

OpenStudy (moongazer):

because i am getting a different answer when i am doing that

OpenStudy (dumbcow):

oh i didn't see that you responded yes it is, either equation would work

OpenStudy (dumbcow):

ok so A = 62/27 5A +C = 11 5(62/27) + C = 11 C = 11 - 310/27 C = 297/27 - 310/27 C = -13/27

OpenStudy (dumbcow):

does that help? see what happened

OpenStudy (moongazer):

why it became C = 297/27 - 310/27 ???

OpenStudy (dumbcow):

rewrote 11 as 297/27 11*(27/27) = (11*27)/27 = 297/27

OpenStudy (moongazer):

ohh i get it now i multplied 5 to 62/7 that is why i am getting a wrong answer :) thanks!

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