Let a,b,c be positive real no.s such that a^3+b^3=c^3.Prove that ..
wait a moment
i dont think you can prove it beyond R^2
they are real numbers not integers
volume behaves differently than area
\[a ^{2}+b ^{2}-c^{2}>6(c-a)(c-b)\]
Have you read about Fermat's Last Theorem? ;P
doesn't apply here
im waiting for the movie :)
I know (we're talking about real numbers), but it reminded me of it. ;P Me too!
if you want to know about Fermat's Last Theorem read Fermat's Enigma.
u saw that google doodle about fermat's theorem
When is the movie coming out amistre ? I hope they didn't make it a vampire movie (too many of them recentlu)
If \[a^3+b^3=c^3,\]then \[a^2+b^2-c^2 \gt 6(c-a)(c-b).\]You can prove this by way of a counter-example: Let \[a=0.\]We then see that \[b^3=c^3,\]\[b=c.\]Consequently, \[b^2-c^2 \gt 6(c-a)(c-b),\]\[b^2-b^2 \gt 6c(c-b),\]\[0 \gt 6b(b-b),\]\[0 \gt 0,\]and we have encountered a contradiction. Therefore, the conclusion is false. QED
@ across "Let a,b,c be positive real "
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