Can someone help explain what a linear equation is? Please give an example.
y=mx+b is a linear equation; represents a line,
y=x is an example
but what do i need to use it for...like how do i know that the question is asking me for that?
y = (f(c))x + c is linear as well
what type of question?
A question that involves lines and planes
on a graph
linear equations are easy to deal with, which is why we try to get the harder stuff into linear form
your going to have to be more specific with a question :)
ok wait....im going to give you a question and help explain it plz...one sec
Write the equation for the line passing through the points (-3, 3) and (0, -3).
when given 2 points; we can draw a line between them right?
yea im pretty sure...thats all the question says and then it shows a graph
the most basic thing to do with 2 points is to determine the slope between them; this is a very important measurement to have
it is the distance and direction that y changes when compared to the distance and direction that x changes
yea i think that slope is rise over run but can u put the y=mx+b thing into use with the coordinates i gave?
given (-3, 3) , (0, -3). y moves from 3 to -3; a distance and direction of -6, right? x moves from -3 to 0; a distance and direction of 3, would you agree?
yes?
Given the two points \((x_1,y_1)\) and \((x_2,y_2)\) \[m = \frac{y_2 - y_1}{x_2 - x_1}\]\[y_1 = mx_1 + b\]Solve for \(b\)
make sure if done the math right :)
how do i solve for b?
the slope then is defines as: the distance and direction of y ------------------------- = -6/3 the distance and direction of x we tend to write the slope in reduced form tho slope = -6/3 = -2 do you agree?
Solve slope equation, then plugin \(m, x_1, y_1\)
ok so can u plug it in so i can see how to do it?
we are working up to that i believe
ok so can u plug it in so i can see how to do it?
ok
im confused...
an easy way to solve for y = mx + b ; given any point and knoing the slope is to simply use a point given and solve for b y = mx + b -mx -mx --------------- y-mx = b
\[(x_1,y_1) = (-3, 3)\]\[(x_2,y_2) = (0, -3)\]\[m = \frac {(-3) - (3)}{(0) - (-3)}\]\[3 = \frac {(-3) - (3)}{(0) - (-3)}(-3) + b\]
so subtract mx from both sides then what?
( x, y) (-3,0) 0 - (-2)(-3) = b b = -6
fill in your slope, y and x to solve for b; then rewrite the formula with the information
y = mx + b y = -2x -6
what does each variable represent?
y is a generic variable for any given point x is also a generic variable for any given point m is the slope that was found and b is also known as the yintercept
the y intercept is the point in which a line crosses it right?
cross the y axis that is
yep; think of the line as the path of a football and the y axis catches, or intercepts it
x intercept is the same concept :)
haha now ur talking my language...thx...im gonna post some more specific questions later ;)
good luck with them :)
yea but it would be good if u answered them cuz u actually made me understand
Given two points \((x_1, y_1)\) and \((x_2, y_2)\) \[m = \frac{y_2 - y_1}{x_2 - x_1}\]\[y_1 = mx_1 + b\] So we have: \[(x_1,y_1) = (-3, 3)\]\[(x_2,y_2) = (0, -3)\]\[m = \frac {(-3) - (3)}{(0) - (-3)} = -2\]\[3 = \frac {(-3) - (3)}{(0) - (-3)}(-3) + b\]\[b = 3 -\frac {(-3) - (3)}{(0) - (-3)}(-3)\]\[b = 3 - (-2)(-3) = 3 - 6 = -3\] Amistre64: Your intercept value was wrong.
Finally: the equation for the line is:\[y= -2x - 3\]
... well its right for the dyslexic point I used :)
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