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Mathematics 14 Online
OpenStudy (anonymous):

Can someone help explain what a linear equation is? Please give an example.

OpenStudy (anonymous):

y=mx+b is a linear equation; represents a line,

OpenStudy (anonymous):

y=x is an example

OpenStudy (anonymous):

but what do i need to use it for...like how do i know that the question is asking me for that?

OpenStudy (amistre64):

y = (f(c))x + c is linear as well

OpenStudy (amistre64):

what type of question?

OpenStudy (anonymous):

A question that involves lines and planes

OpenStudy (anonymous):

on a graph

OpenStudy (amistre64):

linear equations are easy to deal with, which is why we try to get the harder stuff into linear form

OpenStudy (amistre64):

your going to have to be more specific with a question :)

OpenStudy (anonymous):

ok wait....im going to give you a question and help explain it plz...one sec

OpenStudy (anonymous):

Write the equation for the line passing through the points (-3, 3) and (0, -3).

OpenStudy (amistre64):

when given 2 points; we can draw a line between them right?

OpenStudy (anonymous):

yea im pretty sure...thats all the question says and then it shows a graph

OpenStudy (amistre64):

the most basic thing to do with 2 points is to determine the slope between them; this is a very important measurement to have

OpenStudy (amistre64):

it is the distance and direction that y changes when compared to the distance and direction that x changes

OpenStudy (anonymous):

yea i think that slope is rise over run but can u put the y=mx+b thing into use with the coordinates i gave?

OpenStudy (amistre64):

given (-3, 3) , (0, -3). y moves from 3 to -3; a distance and direction of -6, right? x moves from -3 to 0; a distance and direction of 3, would you agree?

OpenStudy (anonymous):

yes?

OpenStudy (anonymous):

Given the two points \((x_1,y_1)\) and \((x_2,y_2)\) \[m = \frac{y_2 - y_1}{x_2 - x_1}\]\[y_1 = mx_1 + b\]Solve for \(b\)

OpenStudy (amistre64):

make sure if done the math right :)

OpenStudy (anonymous):

how do i solve for b?

OpenStudy (amistre64):

the slope then is defines as: the distance and direction of y ------------------------- = -6/3 the distance and direction of x we tend to write the slope in reduced form tho slope = -6/3 = -2 do you agree?

OpenStudy (anonymous):

Solve slope equation, then plugin \(m, x_1, y_1\)

OpenStudy (anonymous):

ok so can u plug it in so i can see how to do it?

OpenStudy (amistre64):

we are working up to that i believe

OpenStudy (anonymous):

ok so can u plug it in so i can see how to do it?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

im confused...

OpenStudy (amistre64):

an easy way to solve for y = mx + b ; given any point and knoing the slope is to simply use a point given and solve for b y = mx + b -mx -mx --------------- y-mx = b

OpenStudy (anonymous):

\[(x_1,y_1) = (-3, 3)\]\[(x_2,y_2) = (0, -3)\]\[m = \frac {(-3) - (3)}{(0) - (-3)}\]\[3 = \frac {(-3) - (3)}{(0) - (-3)}(-3) + b\]

OpenStudy (anonymous):

so subtract mx from both sides then what?

OpenStudy (amistre64):

( x, y) (-3,0) 0 - (-2)(-3) = b b = -6

OpenStudy (amistre64):

fill in your slope, y and x to solve for b; then rewrite the formula with the information

OpenStudy (amistre64):

y = mx + b y = -2x -6

OpenStudy (anonymous):

what does each variable represent?

OpenStudy (amistre64):

y is a generic variable for any given point x is also a generic variable for any given point m is the slope that was found and b is also known as the yintercept

OpenStudy (anonymous):

the y intercept is the point in which a line crosses it right?

OpenStudy (anonymous):

cross the y axis that is

OpenStudy (amistre64):

yep; think of the line as the path of a football and the y axis catches, or intercepts it

OpenStudy (amistre64):

x intercept is the same concept :)

OpenStudy (anonymous):

haha now ur talking my language...thx...im gonna post some more specific questions later ;)

OpenStudy (amistre64):

good luck with them :)

OpenStudy (anonymous):

yea but it would be good if u answered them cuz u actually made me understand

OpenStudy (anonymous):

Given two points \((x_1, y_1)\) and \((x_2, y_2)\) \[m = \frac{y_2 - y_1}{x_2 - x_1}\]\[y_1 = mx_1 + b\] So we have: \[(x_1,y_1) = (-3, 3)\]\[(x_2,y_2) = (0, -3)\]\[m = \frac {(-3) - (3)}{(0) - (-3)} = -2\]\[3 = \frac {(-3) - (3)}{(0) - (-3)}(-3) + b\]\[b = 3 -\frac {(-3) - (3)}{(0) - (-3)}(-3)\]\[b = 3 - (-2)(-3) = 3 - 6 = -3\] Amistre64: Your intercept value was wrong.

OpenStudy (anonymous):

Finally: the equation for the line is:\[y= -2x - 3\]

OpenStudy (amistre64):

... well its right for the dyslexic point I used :)

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