Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

i need help with simplifying an expression

OpenStudy (anonymous):

post it

OpenStudy (anonymous):

\[\sqrt[4]{256x ^{16}}\] assume that all variable are positive my answer sheet says the answer is \[4z ^{4}\]

OpenStudy (anonymous):

\[\left(256 x^{16}\right)^{\frac{1}{4}}\]

OpenStudy (anonymous):

\[256^{\frac{1}{4}} x^4\]

OpenStudy (anonymous):

wait. why did you change it to 1/4th

OpenStudy (anonymous):

\[a^{1/4}=\sqrt[4]{a}\]

OpenStudy (anonymous):

\[(a b)^{\frac{1}{4}}=a^{\frac{1}{4}}b^{\frac{1}{4}}\]

OpenStudy (anonymous):

im sorry but im not following you

OpenStudy (anonymous):

what seems troubling?

OpenStudy (anonymous):

i dont understand your first step. how does that work?

OpenStudy (anonymous):

You can rewrite \[\sqrt[4]{a}\] as \[a^{1/4}\]

OpenStudy (anonymous):

ok so then you divide the ^16 by 1/4 and get 256^1/4 x^4 ?

OpenStudy (anonymous):

According to rule above , I can rewrite as follows:\[\left(256 x^{16}\right)^{\frac{1}{4}}\] Using another rules which states: \[(a b)^{\frac{1}{4}}=a^{\frac{1}{4}}b^{\frac{1}{4}}\] we can change our expression into \[\left(256^{\frac{1}{4}} \left(x^{16}\right)^{\frac{1}{4}}\right)\]

jimthompson5910 (jim_thompson5910):

\[\large \sqrt[4]{256x^{16}}\] \[\large \left(256x^{16}\right)^{\frac{1}{4}}\] \[\large \left(256\right)^{\frac{1}{4}}\left(x^{16}\right)^{\frac{1}{4}}\] \[\large \sqrt[4]{256}\left(x^{16}\right)^{\frac{1}{4}}\] \[\large \sqrt[4]{4^4}\left(x^{16}\right)^{\frac{1}{4}}\] \[\large 4\left(x^{16}\right)^{\frac{1}{4}}\] \[\large 4x^{16*\frac{1}{4}}\] \[\large 4x^{\frac{16}{4}}\] \[\large 4x^{4}\] So \[\large \sqrt[4]{256x^{16}}=4x^{4}\]

OpenStudy (anonymous):

why does the \[\sqrt[4]{?}\] come back on the fouth step?

jimthompson5910 (jim_thompson5910):

I converted back to radical notation because I wanted to take the 4th root of 256 (or 4^4) to get 4

OpenStudy (anonymous):

thanks again :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Breathless: Spooky witch but cute
4 hours ago 3 Replies 0 Medals
Arriyanalol: help
4 hours ago 10 Replies 2 Medals
Arriyanalol: @tinydinoUwU stop trying to find a argument u blad lil boy
1 day ago 5 Replies 4 Medals
Jaded012023: Please tell me what you all think of this song
7 hours ago 6 Replies 1 Medal
Arriyanalol: bro how
7 hours ago 2 Replies 3 Medals
Arriyanalol: cant wait for the new bluey movie in 2027
1 day ago 12 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!