Question

√-4(6+√-25)
multiply, answer in a+bi form.

Answer 1

2i(6+5i) = 12i-10

Answer 2

a=-10
b=12

Answer 3

\[\large \sqrt{-4}(6+\sqrt{-25})\]


\[\large \sqrt{-1*2^2}(6+\sqrt{-1*5^2})\]


\[\large \sqrt{-1}*\sqrt{2^2}(6+\sqrt{-1}*\sqrt{5^2})\]


\[\large i*2(6+i*5)\]


\[\large 2i(6+5i)\]


\[\large 2i(6)+2i(5i)\]


\[\large 12i+10i^2\]


\[\large 12i+10(-1)\]


\[\large 12i-10\]


\[\large -10+12i\]
So \[\large \sqrt{-4}(6+\sqrt{-25})=-10+12i\]