Question

Divide, answer in a+bi form:
9/5i

Answer 1

Multiply both nominator and denominator by i.

Answer 2

\[\large \frac{9}{5i}\]


\[\large \frac{9}{5i}\times\frac{i}{i}\]


\[\large \frac{9i}{5i^2}\]


\[\large \frac{9i}{5(-1)}\]


\[\large \frac{9i}{-5}\]


\[\large -\frac{9i}{5}\]
So \[\large \frac{9}{5i}=-\frac{9i}{5}\]