Question

Calculate EG
a) 2√6
b) √55
c) √73
d) 4.125

Answer 1

none of the above?

Answer 2

there is no none of the above

Answer 3

Can we assume 30, 60, 90, triangles because then we can set up proportions to solve for EG

Answer 4

yea

Answer 5

The triangles are similar. The similar sides are:
|DF|, |EG|, |DE| (hypotenuses)
|DE|, |EG|, |DG| (short side)
|EF|, |GF|, |GE| (long side)

|DF|=11
|GF|=8
|DG|=3

Beyond that, I'm stumped!

Answer 6

okay then to solve this is how I will set it up:
\[8 : x = \sqrt{3}:1\]
We multiply inner and outer terms to get:
\[\sqrt{3}x=8; x = 8/\sqrt{3}\]
By rationalizing denominator (*Basically means multiplying both the numerator and denominator by square root of 2 we get):
\[8\sqrt{3}/3 = 4.6188\]

Answer 7

i get a

Answer 8

it's 2sqrt6. EG (which is the altitude of triangle DEF) can be solved by using geometric mean, which is the square root of the product of the two segments of the hypothenuse.

Answer 9

I'm a little bit of a I think I made an error in my calculation

Answer 10

how did you get a? i am so confused

Answer 11

i wrote my triangles separately

Answer 12

square root of 3 time 8

Answer 13

square root of 3 times 8 = 2 sqrt 6

Answer 14

can u guys help me find de?

Answer 15

i didn't even use the last triangle i made
you know this is one of the ways to prove the Pythagorean thm right?

Answer 16

well if you have EG all you have to use it Pythagoras theorem
\[a ^{2}+b ^{2}=c ^{2}\] to find de

Answer 17

did you look at my pdf sadia?

Answer 18

de?

Answer 19

yea thanks myininayay

Answer 20

yea de

Answer 21

(DE)^2=3^2+(2sqrt(6))^2)=33
DE=sqrt33

Answer 22

you guys were a huge help thanks a lot!

Answer 23

gj sox

Answer 24

thanks!