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what is...
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This is not the philosophy section.
But I think, therefore I am.
depends on what is is. bill clinton
hahahaha e^(-x^2)
well for one thing it is \[\frac{1}{e^{x^2}}\]
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but not really sure of the question. it looks like a bell curve http://www.wolframalpha.com/input/?i=y%3De^%28-x^2%29
looks like the statistics "error" function
in fact if you divide by \[2\pi\] you get the normal curve exactly. that is because \[\int_{-\infty}^{\infty}e^{-x^2}dx=2\pi\] and so \[\frac{1}{2\pi}\int_{-\infty}^{\infty}e^{-x^2}dx=1\]
still not sure what "is" is though...
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