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Mathematics 7 Online
OpenStudy (anonymous):

what is...

OpenStudy (anonymous):

This is not the philosophy section.

OpenStudy (anonymous):

But I think, therefore I am.

OpenStudy (anonymous):

depends on what is is. bill clinton

OpenStudy (anonymous):

hahahaha e^(-x^2)

OpenStudy (anonymous):

well for one thing it is \[\frac{1}{e^{x^2}}\]

OpenStudy (anonymous):

but not really sure of the question. it looks like a bell curve http://www.wolframalpha.com/input/?i=y%3De^%28-x^2%29

OpenStudy (anonymous):

looks like the statistics "error" function

OpenStudy (anonymous):

in fact if you divide by \[2\pi\] you get the normal curve exactly. that is because \[\int_{-\infty}^{\infty}e^{-x^2}dx=2\pi\] and so \[\frac{1}{2\pi}\int_{-\infty}^{\infty}e^{-x^2}dx=1\]

OpenStudy (anonymous):

still not sure what "is" is though...

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