Question

rationalize denominator:
5/8+√x

Answer 1

\[\large \frac{5}{8+\sqrt{x}}\]



\[\large \frac{5}{8+\sqrt{x}}\times\frac{8-\sqrt{x}}{8-\sqrt{x}}\]



\[\large \frac{5(8-\sqrt{x})}{(8+\sqrt{x})(8-\sqrt{x})}\]



\[\large \frac{40-5\sqrt{x}}{64-x}\]

So \[\large \frac{5}{8+\sqrt{x}}=\frac{40-5\sqrt{x}}{64-x}\]

Answer 2

is this fully simplified?

Answer 3

Yes it's fully simplified

Answer 4

dang, it's not correct...

Answer 5

oh crap... sorry, it is right :)

Answer 6

Yeah the computer is real picky