Question

jim thompson, can you come here?

Answer 1

do u need somethin?

Answer 2

well was wondering how to write in = in the equation coding. like "\[fac{1}{2}\+\4\ =? 4.5\ "

Answer 3

k nvm i dont know i nvr use, i find it retarded

Answer 4

it's awesome lol

Answer 5

\[\frac{it is}{awesome}\]

Answer 6

yh but it takes long

Answer 7

\[\frac{does}{it?}\]

Answer 8

ok I'm here, what's up?

Answer 9

new one, so I can give you medals.

Answer 10

but lol, I was asking you to come so I could figure out some code

Answer 11

ok don't really mind about the medals, what's on your mind code wise?

Answer 12

I think the "=" in that code looks funny, thought there was a different way to do it. was going to ask you about it.

Answer 13

show me

Answer 14

or is it back in that last post?

Answer 15

I guess I got it. \[=is equals i guess\]

Answer 16

do they use nbsp for spaces in this code? what language is this anyway?

Answer 17

LaTex

Answer 18

lol what

Answer 19

use a single lone \ for space

Answer 20

it's a markup language like HTML

Answer 21

\ [testing the code\ ] ---> \[testing the code\]


\ [testing \ the \ code\ ] ---> \[testing \ the \ code\]


better to use \textrm instead


\ [\textrm{testing the code}\ ] ----> \[\textrm{testing the code}\]

Answer 22

textrm is a way to display printed text as opposed to mathematical expressions

Answer 23

cool, I'll brush up on it to help others :)

Answer 24

great, to learn more, there are tons of LaTex tutorials out on the web

Answer 25

seems pretty easy to learn..

Answer 26

you could also try Tex, but LaTex should be more than enough

Answer 27

yeah it's not too bad

Answer 28

I play around with lua alot so I'm familiar with code.

Answer 29

what's that syntax like

Answer 30

print("helloworld")

Answer 31

useful for text based games.

Answer 32

oh so like C?

Answer 33

c based. way easier, slower, still pretty fast and powerful.

Answer 34

i "C"....

Answer 35

but if you know C then you can pick LUA up in about an hour and start OWNING everyone on text based games haha.

Answer 36

lol cool i know a bit of C

Answer 37

Yeah I wish there were 89 people on the computer science section at all times. would be awesome.

Answer 38

I'm sure there are plenty of sites though that specialize in that sort of thing

Answer 39

nothing as interactive as this.

Answer 40

true

Answer 41

this sight is fanflutteringtastic. I predict A+ in precalc next year.

Answer 42

Anyways, wanna werk my problem ^^?

Answer 43

sure, what was it again?

Answer 44

wait one sec while I get it

Answer 45

\[\frac{1}{x}\ + \frac{1}{2x}\ + \frac{1}{3x}=12\]

Answer 46

just so it's close by

Answer 47

multiply EVERY term by the LCD 6x to get

\[6 +3+2=72x\]

Answer 48

oh hold up.

Answer 49

Now solve like its any other equation

6+3+2=72x
11=72x
x=11/72

Answer 50

I'm so bad at finding LCD. I thought it was (x)(2x)(3x)

Answer 51

any tips for finding the LCD in this case?

Answer 52

Answer is \[\large x=\frac{11}{72}\]

Answer 53

;D thanks. I got another one. wanna see?

Answer 54

(x)(2x)(3x) = 6x^3 is one common denominator but it is not the LCD

Answer 55

the LCD can be found by finding the LCD between x and 2x (which is 2x) then finding the LCD between 2x and 3x (which is 6x). So you have to do it in pairs like this, you can't just multiply them out


You can do that to get a common denominator (not the LCD though), but things might get messy.

Answer 56

\[\frac{1}{x-1}+\frac{8}{x²-6x+5)+frac{5}{x-5}\] what is it mad about?

Answer 57

wait, i don't understand how finding the LCD between x and 2 is relative to 6?

Answer 58

between x and 2x

Answer 59

To find the LCD among a group of expressions, you have to find the LCD in pairs.


For instance, to find the LCM of 5, 6 and 8, first find the LCD of 5 and 6 (which is 30). Now take the LCM of 30 use it in conjunction with 8 to find that the LCM of 30 and 8 is 120

So the LCM (LCD if it's a denominator) of 5, 6, and 8 is 120

Answer 60

\[\frac{1}{x-1}+\frac{8}{x²-6x+5}=\frac{5}{x-5}\] there we are.

Answer 61

Thanks man. That really messed me up in alg 2!

Answer 62

btw in your last attempt you had +frac{5}{x-5} instead of +\frac{5}{x-5}, just caught that

Answer 63

so the lcd here, I'm just guessing, is it x²-6x+5?

Answer 64

good guess

Answer 65

:D

Answer 66

x^2-6x+5=(x-1)(x-5), so this is the smallest multiple of both x-1 and x-5

Answer 67

so multiply everything through by this LCD to get...

Answer 68

wait the lcm is (x-5)(x-1) .. I'm confused.

Answer 69

I mean the polynomial and those two binomials are = to one another.. and it would be easier to multiply by (x-5)(x-1)

Answer 70

yeah if you didn't recognize they were equal or forgot they were, it's better to multiply by (x-5)(x-1) so you can see which pieces cancel out and which stay

Answer 71

shaman, so we should get,... here let me do it on paper

Answer 72

hmm would the x²-6x+5 cancle with the LCD?

Answer 73

yes, that second term will have nothing left over

Answer 74

so x =1

Answer 75

that's what you're getting for your final answer?

Answer 76

>.< don't sound so skeptical; yes.

Answer 77

because (x-1) cancels in the first term.. leaving (x-5)+8=5(x-1)

Answer 78

oh...

Answer 79

hmm..

Answer 80

gotta multiply the bottom too right?

Answer 81

could you show me your work lol I'm confused.

Answer 82

could you show me your work lol I'm confused.

Answer 83

this is what I got

\[\large \frac{1}{x-1}+\frac{8}{x^2-6x+5}=\frac{5}{x-5}\]



\[\large (x-5)(x-1)\frac{1}{x-1}+(x-5)(x-1)\frac{8}{x^2-6x+5}=(x-5)(x-1)\frac{5}{x-5}\]



\[\large 1(x-5)+8=5(x-1)\]



\[\large x-5+8=5x-5\]



\[\large x+3=5x-5\]



\[\large x-5x=-5-3\]



\[\large -4x=-8\]



\[\large x=\frac{-8}{-4}\]



\[\large x=2\]

Answer 84

oh I must have just made a lill mistake

Answer 85

where at?

Answer 86

I tried to combine like terms. the -5 and 8 on the left

Answer 87

so i had x - 3 lol

Answer 88

ah

Answer 89

anyways man. You rock. You should be paid for this.

Answer 90

I do (sometimes) lol

Answer 91

lol. this site should pay you I mean.

Answer 92

but this is fun so no worries

Answer 93

IKNOWRIGHT? since when is math fun XD

Answer 94

if you were paid by medals, then it'll be a popularity contest

Answer 95

I'd rather do this than play games.

Answer 96

yeah for sure.

Answer 97

so idk how paid tutors would work on this site, but I see it happening someday

Answer 98

I dunno. People reccomended. Or people that spend as much time on here as you do?