Question

Help! I will type question,TK

Answer 1

well, this is basically: \[\sqrt[3]{(x-6)^2}=8\]

Answer 2

sorry exponent is 3/2
not 2/3

Answer 3

its x=sqrt(2)+6

Answer 4

well, still we can the simply square both sides and get: (x-6)^3=8^2

Answer 5

http://www.wolframalpha.com/input/?i=cuberoot((x-6)^2))%3D8&t=crmtb01

Answer 6

\[(x-6)^{\frac{3}{2}}=8\]

Answer 7

which would the give us: x^3-18x^2+108x-216=64

Answer 8

yes,I did than what next ?

Answer 9

how you factor find x ?

Answer 10

then subtracting 64 from both sides we get: x^3-18x^2+108x-280

Answer 11

well, we can factor by grouping i hope

Answer 12

(x^3-18x^2)+(108x-280)

Answer 13

I.m stuck ffrom here

Answer 14

x^2(x-18)+4(27x-70)

Answer 15

but that really wont help us

Answer 16

i suggest we use this form: (x-6)^3=64

Answer 17

that an anwser?
wolf answer x=10 ,I spend many hours can't get x=10

Answer 18

i mean x-6=4

Answer 19

the add 6 to both sides and get: x=10

Answer 20

wow, that relatively easy

Answer 21

to think that we went all the way with the factoring.

Answer 22

I see good help, I spend many hours , can't get x=10 ,TY

Answer 23

np