Question

JIM!

Answer 1

hey

Answer 2

yo :) much better.

Answer 3

lol wtf?

Answer 4

so rewrite the exponential equation as a log

Answer 5

our crappy way of direct chat hahd lol

Answer 6

lol

Answer 7

mybrainvsme<-- what does ur username mean?

Answer 8

3^4 = 81
is 3log81? I can't remember lol

Answer 9

mybrainvsme<-- what does ur username mean?

Answer 10

convert to same base

Answer 11

it means I struggle to learn. It's sort of like... um I dunno can't remember the grammatical term.

Answer 12

\[\large 3^4=81\] converts to \[\large \log_{3}(81)=4\]

Answer 13

mybrainvsme<-- what does ur username mean?

Answer 14

81log3=4

Answer 15

oh makes sense.

Answer 16

is there a latex code for logs? :D

Answer 17

yes \log_{b}(x) ---> \[\log_{b}(x)\]

Answer 18

:D cool.

Answer 19

36^1/2 = 6 lol is there latex for ^exponents?

Answer 20

^{\frac{1}{2}}

Answer 21

cool beans. I think I can do this one..

Answer 22

great

Answer 23

\[log_{36}{6}=.5\]

Answer 24

Good or \[\large \log_{36}{6}=\frac{1}{2}\]

Answer 25

yeah didn't feel like writing frac{1}{2} lol

Answer 26

lol ok as a shortcut you can type \frac12 instead of \frac{1}{2} but it only works for single digit fractions so it's not too useful

Answer 27

\9^{\frac{1}{2}} shouldn't that work?

Answer 28

\ [ 9^{\frac{1}{2}} \ ] ---> \[\large 9^{\frac{1}{2}}\]

\ [ 9^{\frac12} \ ] ---> \[\large 9^{\frac12}\]

Answer 29

cool beans.
so \[9^{m}\ =37\] is \[log_{9}{37}=m\]

Answer 30

yep you got it

Answer 31

nice :)

Answer 32

okay can we simplify some logs?

Answer 33

sure

Answer 34

oh are you talking about these logs or other ones you haven't posted yet?

Answer 35

okay
\[\log_{3}{9}\] <--- simplify.

Answer 36

let \[\large y=\log_3(9)\]

So \[\large 3^y=9\]


\[\large 3^y=3^2\]


\[\large y=2\]

Answer 37

why am I making it = y lol? Is that just how you simplify logs?

Answer 38

or...

\[\large \log_3(9)\]


\[\large \frac{\log_{10}(9)}{\log_{10}(3)}\]


\[\large \frac{\log_{10}(3^2)}{\log_{10}(3)}\]


\[\large \frac{2\log_{10}(3)}{\log_{10}(3)}\]


\[\large 2\]
So \[\large \log_3(9)=2\]

Answer 39

oh yeah that works better

Answer 40

so how did you know to take the square root of 9?

Answer 41

Yeah basically I recognized that 9 is a power of 3 and logs deal with powers and exponents.

Answer 42

a power of 3? or 2?

Answer 43

Yeah basically I recognized that 9 is a power of 3 and logs deal with powers and exponents.

Answer 44

9 is a power of 3 since \[\large 3^2=9\]

Answer 45

ah I see.

Answer 46

no room on my paper :P

Answer 47

okay sorry I'm taking so long

Answer 48

Yeah basically I recognized that 9 is a power of 3 and logs deal with powers and exponents.

Answer 49

np

Answer 50

Yeah basically I recognized that 9 is a power of 3 and logs deal with powers and exponents.

Answer 51

weird...the order of the posts just changed

Answer 52

so
\[\log_{3}{81}\] are you sure we are simplifying and not evaluating?

Answer 53

In this case, it's the same thing.

Answer 54

so log base 10 3 log base 10 81?

Answer 55

81 is 3^3 right?

Answer 56

3^4

Answer 57

so the answer to this would just be 4?

Answer 58

yep

Answer 59

it's asking: the base (3) to what power is the result 81?

Answer 60

to the 4?

Answer 61

it's asking: the base (3) to what power is the result 81?

Answer 62

yep \[\large 3^4=81\]

Answer 63

\[4\frac{\log_{3}}{\log_{3}}\]

Answer 64

lol like that?

Answer 65

lol yes something like that

Answer 66

haha, I take so long to write my code, I don't even notice you've already answered my question.

Answer 67

but don't sweat over the small stuff

Answer 68

sha. um okay let me find one I might struggle with.

Answer 69

:D natural logs? LNe^5

Answer 70

ah natural logs, probably the most unnatural thing to come across since you start off with logs lol

Answer 71

natural logs are logs but they're special logs with base e

Answer 72

ie \[\large \ln(x)=\log_{e}(x)\]

Answer 73

so instead of saying log base e all the time, we use ln (LN) instead

Answer 74

sha. so this is the same as \[\log_{e}{5}\] ?

Answer 75

lol no can't be right.

Answer 76

close, it's the same as \[\large \log_{e}(e^5)\]

Answer 77

lol just wrote that down as you posted it :)

Answer 78

could you show me the code for that log you just posted?

Answer 79

cool, so you can take the exponent down and then evaluate the log base e of e to get 1. So you'll be left with 5.

Answer 80

\large \log_{e}(e^5)

Answer 81

oh yeah I remember that from class.

Answer 82

btw you can see any code you want by right clicking the image and selecting "show source"

Answer 83

Oo?

Answer 84

hey how would I put large and red in the same bit of code, for coloring.

Answer 85

?*

Answer 86

\ [\color{red}{hello} \ \color{blue}{there}\ ] ---> \[\color{red}{hello} \ \color{blue}{there}\]

Answer 87

keep in mind you have to keep it in the { } or else you get only one letter colored and the rest remains black

Answer 88

\[\large\color{red}{okay}\]

Answer 89

cool you got it

Answer 90

:D

Answer 91

okay here is one. \[\log_{y}{\frac{1}{y^4}}\]

Answer 92

oo, should of put ( ) in there.

Answer 93

that's ok

Answer 94

keep in mind that \[\large \frac{1}{y^4}=y^{-4}\]

Answer 95

wouldn't the y's cancel then leaving just -4?

Answer 96

yep

Answer 97

\[\log_{3}{81}\]

Answer 98

we did this one already, it's 4