Question

2 over 7v^2-7v - 3 over 7v-7

Answer 1

if you fact the denominaotr of the first fraction it will be easir

Answer 2

\[\frac{2}{7v^{2}-7v} -\frac{3}{7v-7}\]
??
is that it

Answer 3

oh wow i read tht wrong

Answer 4

yeah

Answer 5

how did u get the line I could not figure that out.

Answer 6

MULTIPLY RIGHT BY v!

Answer 7

hahah

Answer 8

factor the denominators like Lagrange said

Answer 9

2/(7v(v-1)) - 21/(7v(v-1))

Answer 10

to get the fraction bar
use "frac{top}{bottom}" notation in equation editor

Answer 11

it said it was not right

Answer 12

how'd you get -19?

Answer 13

not quite
you multiplied the 3 by 7 instead of v

Answer 14

yeah it should be someting like 2-3v/LCD

Answer 15

Or GCD or whatever

Answer 16

right my bad

Answer 17

so that is the answer

Answer 18

I believe so unless there is any other simplifying it should be 2-3v/7v^2-7v

Answer 19

(2-3v)/7v(v-1)

Answer 20

yes what outcast said

Answer 21

yes that is correct

Answer 22

sorr i am really tired today

Answer 23

\[({2}\div{7v^{2}-7v})-({3}\div{7v-7})\]
\[({2-3v})\div({7v^{2}-7v})\]
\[{(2-3v)}\div{(7v(v-1))}\]