simplify:((2x^2+9x+9)/(x+1))/((10x^2+19x+6)/(5x^2+7x+2))
and yes this is a fraction within a fraction
where is dumbcow?
everything will be easier when you factor, in the first fraction factor the numerator.In the second fraction factor both the numerator and denominator
times by reciprical and solv
yeah what they said
ok
that is an insane polyomial there
ya our school does that to us sometimes
I know what you mean. I love it when our SI says "What he didn't teach you this" a week after class
"Telescoping a series for divergence is not needed".... Well when the book asks you...
whenever you are dividing by a fraction, rewrite so you are multiplying by reciprocal \[\frac{\frac{1}{x}}{\frac{3}{x}} = \frac{1}{x}*\frac{x}{3}\]
or finding the sum of a sequence i mena
ok dumbcow you make it so much clearer.. thanks
and you too outkast
hows the factoring going? everything factors and almost everything cancels answer -> x+3
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