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OpenStudy (anonymous):
simplify:((2x^2+9x+9)/(x+1))/((10x^2+19x+6)/(5x^2+7x+2))
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OpenStudy (anonymous):
and yes this is a fraction within a fraction
OpenStudy (anonymous):
where is dumbcow?
OpenStudy (anonymous):
everything will be easier when you factor, in the first fraction factor the numerator.In the second fraction factor both the numerator and denominator
OpenStudy (anonymous):
times by reciprical and solv
OpenStudy (dumbcow):
yeah what they said
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
that is an insane polyomial there
OpenStudy (anonymous):
ya our school does that to us sometimes
OpenStudy (anonymous):
I know what you mean. I love it when our SI says "What he didn't teach you this" a week after class
OpenStudy (anonymous):
"Telescoping a series for divergence is not needed".... Well when the book asks you...
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OpenStudy (dumbcow):
whenever you are dividing by a fraction, rewrite so you are multiplying by reciprocal
\[\frac{\frac{1}{x}}{\frac{3}{x}} = \frac{1}{x}*\frac{x}{3}\]
OpenStudy (anonymous):
or finding the sum of a sequence i mena
OpenStudy (anonymous):
ok dumbcow you make it so much clearer.. thanks
OpenStudy (anonymous):
and you too outkast
OpenStudy (dumbcow):
hows the factoring going?
everything factors and almost everything cancels
answer
-> x+3
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