Mathematics
13 Online
OpenStudy (anonymous):
Use P series to determine convergence of divergence
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[\sum_{n=1}^{\infty}6/n^(1.06)\]
OpenStudy (anonymous):
the bottom is n^1.06
OpenStudy (anonymous):
Ah man why calc, told u havent taken it in school yet
OpenStudy (anonymous):
ono joe is here better find out faster!
OpenStudy (anonymous):
look up p series this question squite simple
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
it requires no calc at all
OpenStudy (anonymous):
fine NO ONE DO THIS PLS
OpenStudy (anonymous):
btw u mean or divergence right?
OpenStudy (anonymous):
i mean convergent of divergent
OpenStudy (anonymous):
or* yes
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
idk why i keep putting of?
OpenStudy (anonymous):
so it's either divergent or convergent
OpenStudy (anonymous):
well it converges for sure
OpenStudy (anonymous):
it can't be divergent i meant either or... so you get your medal =]
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
still figuring out how to calculate, yes n>1
OpenStudy (anonymous):
i mean exponent of n
OpenStudy (anonymous):
there is no need for calculation
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
yeah i dont even know how to calculate it... it was never taught unless it is taught in another class riemann zeta is completely new to me