Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Use P series to determine convergence of divergence

OpenStudy (anonymous):

\[\sum_{n=1}^{\infty}6/n^(1.06)\]

OpenStudy (anonymous):

the bottom is n^1.06

OpenStudy (anonymous):

Ah man why calc, told u havent taken it in school yet

OpenStudy (anonymous):

ono joe is here better find out faster!

OpenStudy (anonymous):

look up p series this question squite simple

OpenStudy (anonymous):

it requires no calc at all

OpenStudy (anonymous):

fine NO ONE DO THIS PLS

OpenStudy (anonymous):

btw u mean or divergence right?

OpenStudy (anonymous):

i mean convergent of divergent

OpenStudy (anonymous):

or* yes

OpenStudy (anonymous):

idk why i keep putting of?

OpenStudy (anonymous):

so it's either divergent or convergent

OpenStudy (anonymous):

well it converges for sure

OpenStudy (anonymous):

it can't be divergent i meant either or... so you get your medal =]

OpenStudy (anonymous):

still figuring out how to calculate, yes n>1

OpenStudy (anonymous):

i mean exponent of n

OpenStudy (anonymous):

there is no need for calculation

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

yeah i dont even know how to calculate it... it was never taught unless it is taught in another class riemann zeta is completely new to me

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!