Question

how much power is needed to lift 200-n object to a height of 4m in 4 s ?

Answer 1

velocity is 1m/s. W = KEf - KEi. (where f=final and i=initial). KE =1/2mv^2. KEi=0 because initial velocity is 0, so W=KEf=1/2mv^2=1/2*m*1. Just plug in mass

Answer 2

is 200-n the mass, or a 200 newton object?

Answer 3

power=work/time

work=mgh
=200*10*4=8000J
power=8000/4=2000W

Answer 4

newton object

Answer 5

2000w

Answer 6

so you got it.