Question

CAN SOMEBODY PLEASSSSEEEE CONFIRM MY ANSWERS ?!!!!! Find an equation of the tangent line to the graph of the function at the point (0,1). y = e2x and the answer I got is y=2x+1

Answer 1

\[\large y=e^{2x}\]


\[\large y'=2e^{2x}\]


Slope at (0,1): \[\large y'=2e^{2(0)}=2\], so slope is m=2

The y-intercept is (0,1), so b=1 meaning that y =mx+b becomes y = 2x+1

So you have the right answer.

Answer 2

THANK YOU SOOO MUCHHH FOR REPLYING. I REALLY APPRECIATE IT. :)

Answer 3

THANK YOU SOOO MUCHHH FOR REPLYING. I REALLY APPRECIATE IT. :)