Question

Given that
(1+x)^5 (1+ax)^6 = 1+bx + 10x^2 + ............................. + a^6x^11
fine the values of a, b

Answer 1

I would begin by expanding the left hand side

Answer 2

That part I figured out but then what?

Answer 3

well, then after you that, The x^2 term in the expansion on the right will be formed from:

(1) *(15a^2x^2) + (5x)*(6ax) + (10x^2)*(1)
= [15a^2 + 30a + 10] * x^2

Answer 4

now, that should be equal to 10x^2

Answer 5

now we can write this:

15a^2+30a+10=10

Answer 6

then just solve that

Answer 7

for you values of a

Answer 8

oooooh I get it now thank you

Answer 9

np