Question

log2(8-6x)=5

Answer 1

\[\log_b(x)=y\iff b^y=x\] so put
\[8-6x-2^5\] and solve for x

Answer 2

i think you are missing an equal sign

Answer 3

\[\log2{8-6x} = \log2{32} --> 8-6x = 32 \]

Answer 4

\[8-6x=2^5\]rather.

Answer 5

saellite failed :)

Answer 6

:)

Answer 7

we call that a "typo" lol

Answer 8

any 'mistake' is a typo...that's my motto

Answer 9

i call typing 1/(cos(x)) instead of cos(x) also a type zarkon!

Answer 10

lol

Answer 11

i call writing sinx instead of sin(x) a typo!

Answer 12

shhh

Answer 13

i will keep it to myself

Answer 14

do you need further assistance on your problem calebson?

Answer 15

yes

Answer 16

lets finish
\[8-6x=2^5\]
\[8-6x=32\]
\[-6x=24\]
\[x=-4\]

Answer 17

there you go! lol

Answer 18

thanks

Answer 19

from all of use
you are welcome

Answer 20

this problem was all me

Answer 21

I have one more for you guys i think there is no solution though

Answer 22

by the way 8-6x have to be bigger then 0 so 6x<8 and there for x<3/4 dont forget to check it while using logs

Answer 23

sry x<4/3