Question

sqrt(2/9)... write in form of sqrt(a)/b it says sqrt(2)/3 is incorrect

Answer 1

\[\large \sqrt{\frac{2}{9}}=\frac{\sqrt{2}}{3}\] is correct, so there has to be a typo somewhere

Answer 2

there's no typo i shows me what it looks like before i submit the answer, im thinking maybe i'm not suppose to be using square roots is there another way to put it?

Answer 3

but it says right in the directions to use square roots, so something is wrong

maybe they just want the values of 'a' and 'b'?

Answer 4

Since the square root is a plus 3 as well as a minus 3 they are asking for\[\sqrt{2}\over \pm3\]

Answer 5

the "plus/minus" only comes up when solving quadratics

Answer 6

Has always been a point of confusion for me.

Answer 7

(-3)(-3)=9 The definition of a square root is a factor times itself....

Answer 8

But the square root is a function. So one input gets mapped to one output. This means that the square of some positive number is positive (and not negative at the same time)

Answer 9

There's a difference between \[\sqrt{3}\] and \[\pm\sqrt{3}\], the latter results in solving \[x^2=3\]

Answer 10

You're right about definition of function.

Answer 11

i cant enter +/- it wont let me

Answer 12

I still can't see why pinksweety gets an incorrect solution!

Answer 13

yeah that's why I'm thinking it's a typo on their end (ie the program's fault)

Answer 14

it very well maybe the programs fault, its new this is the first semester they are using it

Answer 15

If she had left a radical in the denominator, I can see why they might have docked her for not simplifying putting the radical in the numerator

Answer 16

In this case I can't see pinksweety getting a better answer.

Answer 17

best to just bring it up to an actual human so they can sort this out

Answer 18

I would move on pinksweety.

Answer 19

hang on it says "rationalize the denominator of the expression" does that mean anything?

Answer 20

the denominator 3 is already a rational number