Question

how is a higher order root is different from a square root ?

Answer 1

estudier i got it :)

Answer 2

In principle, there is no difference.

n th root of x is a number a such that a^n is x.

If u mean the radical in the case of a square root, then that means the positive root, a practice not followed for higher order roots.

Answer 3

but thanks anyway :)

Answer 4

np:-)

Answer 5

now i need yur help lol

Answer 6

Explain, in complete sentences, the effect of the difference of squares pattern on the multiplication of radicals

i dont get it

Answer 7

I think what they are talking about here is rationalizing a denominator that contains a square root.

In order to get rid of something like a + sqrt b in the denominator u would usually multiply top and bottom by a- sqrt b resulting in

( a + sqrt b)(a- sqrt b) = a^2 - b^2 or the difference in squares pattern.

Answer 8

U could extend the principle to higher order roots as well.

Answer 9

i think The difference between square patter on the multiplication of radicals is multiplying the radical by its conjugate. , am I right ?

Answer 10

Yes, that's the situation described above.

Answer 11

how can i provide an example

Answer 12

Use the one I just put...

Answer 13

Okay

Answer 14

Put something simple on the top like a or b...

Answer 15

top of what?

Answer 16

So like a/( a + sqrt b) -> a( a + sqrt b) /( a + sqrt b)(a- sqrt b) ->

a( a + sqrt b)/(a^2-b^2)

Answer 17

If you want to put numbers, choose nice ones like 5 and 3 etc...

Answer 18

I think the algebra clearly shows the pattern though...

Answer 19

Ok thanks