Question

Represent \[\sin^{-1} \] (2ax sqrt{1-a^2 x^2}), -1/sqrt{2} le ax ge -1/sqrt{2} in the simplest form.

Answer 1

\[\sin^{-1} (2ax \sqrt{1-a^2x^2}), \]\[-1/\sqrt{2} \le 1/\sqrt{2} \] in the simplest form

Answer 2

\[ \sin^{-1}(2ax \sqrt{1-a^2 x^2}), -1/\sqrt{2} \le ax \ge -1/\sqrt{2} \]

Answer 3

lol

Answer 4

hmm this looks ugly :)

Answer 5

sorry i meant greater than or equal to 1/sqrt{2}

Answer 6

im not sure what to do really

Answer 7

i kindof don't understand the question

Answer 8

what to do now

Answer 9

so this is exactly how the questions reads?

Answer 10

?

Answer 11

is it
\[-1/\sqrt{2}\le ax \le 1/\sqrt{2}\]

Answer 12

yea the inequality you had didn't make sense

Answer 13

say something back please lol

Answer 14

so
\[\pi/2 \le \sin^{-1}(2ax \sqrt{1-a^{2}x^{2}}) \le 3\pi/2\]

Answer 15

yes

Answer 16

what?

Answer 17

how did you get that cow?

Answer 18

yes how did u get that dumbcow

Answer 19

i plug in 1/sqrt2 and -1/sqrt2 for ax

Answer 20

so thats what we want?

Answer 21

yes

Answer 22

ok...

Answer 23

really thats it?
bad question wording
that was not simplifying

Answer 24

hmn

Answer 25

so what can i do now 1

Answer 26

no help

Answer 27

i don't know what the question is sorry

Answer 28

r u on facebook

Answer 29

yes

Answer 30

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