Question

. Given an equation zsq+ 1/zsq = 1 , solve for z in polar form

Answer 1

\[z ^{2} + 1/ z ^{2} = 1\]

Answer 2

oh that was z^2
lol

Answer 3

Do you know if Z is a complex number or is it just a random variable like X?

Answer 4

Its a random variable like X

Answer 5

i get
\[z^{2} = \frac{1}{2} \pm \frac{\sqrt{3}}{2}i\]

Answer 6

which in polar form is
\[z^{2} = \cos \pi/3 +i \sin \pi/3\]

Answer 7

The answer is \[1 Angle \pi/6\]

Answer 8

hmm
z = pi/6 is the answer

Answer 9

oh wait, its that one rule i forget the name
\[z = [\cos \pi/3 + i \sin \pi/3]^{1/2}\]
\[z = (1/2)(\cos \pi/6 + i \sin \pi/6)\]

Answer 10

does that look right??

Answer 11

Looks good to me lol.

Answer 12

its De Moivres theorem
i did a little wrong though
the 1/2 should not be out front
\[z =(\cos \pi/6 + i \sin \pi/6)\]

Answer 13

ouhkk, thanks