x^2+7x+12 factorise completely please help me.
(x+4)(x+3)
how. plz show full woking
look at the last term first
what are the multiples of 12? (what multiply together to make 12?)
1,12 3,4 6,2
Do any of those numbers add or subtract from their partner to get you 7, the middle term?
only 3 and 4
since 12 is positive, and only a negative number times a negative number -or- a positive number times a positive number get you a positive, 3 and 4 are either -3,-4 or 3,4
Now, is 7 positive or negative?
it's positive
so 3 and 4 have to be positive too. if they were negative, it would be a negative 7
So far wh have ( 3)( 4)
Now the last step. the first term is x^2.
the coefficaint is 1, so your terms will be x and x. (x*x=x^2)
well, in my point of view, it is just easier to rewrite x^2+7x+12 as x^2+4x+3x+12 Now x^2+4x+3x+12=x(x+4)+3(x+4) distributive property (x+4)(x+3)
so finally you have (x+4)(x+3)
p.s. once you do this a few more times, it will get a lot easier; I just wrote everything out so you wouldn't be confused by a step.
x^2+7x+12 =x^2+4x+3x+12 =x(x+4)+3(x+4) =(x+4)(x+3)
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