A new car is purchased for $45,000. During the next 5 years, the rate of change in the value of the car is given by the differential equation dx/dt = -kx, where $x is the value of the car after t years, and k is a constant. After 5 years, the car is expected to have a value of $15,000. Find the value of the car when it is 3 years old.
Solve the general ODE and get y=Ce^kt. Plug in 5 years and 15,000 to solve for the constant of integration, then plug in the 3 years and solve.
if you don't mind me saying, this is a really dumb way dx/dt blah blah to solve this question. you know that in 5 years it will be worth 1/3 of its current value, so all you need to do is plug in 3 into the easy formula \[45\times (\frac{1}{3})^{\frac{t}{5}}\]
in thousands of course. just compute \[45(\frac{1}{3})^{\frac{2}{3}}\] and be done
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