Question

can someone help me figure out this integral, i will write it out

Answer 1

\[\int\limits_{}^{}(x+sinx)^3+cosx(x+sinx)^3 dx\]

Answer 2

u substitution

Answer 3

u=x+sinx

Answer 4

Let u=(x + sinx)

Answer 5

okay so then du=1+cosx dx

Answer 6

right

Answer 7

But first, use distributive property to re-write it like this:

\[\int\limits\limits_{}^{}(x+sinx)^3(1+cosx) dx\]

Answer 8

That ought to make it easier

Answer 9

how though if you distriubte cosx into (x+sinx), how do you get 1+cosx

Answer 10

You distribute (x+sinx)^3 out of 1 + cosx not into it

Answer 11

distributive property is obviously ab+ ac = a(b+c)....use your imagination here

Answer 12

i still cant see that

Answer 13

twiddla

Answer 14

okay where

Answer 15

http://www.twiddla.com/solved

Answer 16

oh i see it, how you did it

Answer 17

now i let u-1+sinx right

Answer 18

wait, no u still equals x + sin x

Answer 19

so will the answer be (1/4)(x+sinx)^4

Answer 20

yes

Answer 21

+ C

Answer 22

thanks man

Answer 23

\[\frac{(x+\sin(x))^4}{4}+c\]