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Mathematics 8 Online
OpenStudy (anonymous):

3/8(5+6x)+3>21

OpenStudy (anonymous):

\[\frac{3}{8(5+6x)+3}>21\] this ?

OpenStudy (anonymous):

subtract 3 multiply by 8/3 subtract 5 divide by 6

OpenStudy (anonymous):

@imran i am guessing it is \[\frac{3}{8}(6+5x)+3=21\]

OpenStudy (anonymous):

ok, that's probably more likely

OpenStudy (anonymous):

either way is correct

jimthompson5910 (jim_thompson5910):

3/8(5+6x)+3>21 3/8(5+6x)>21-3 3/8(5+6x)>18 3(5+6x)>144 15+18x>144 18x>144-15 18x>129 x>(129)/(18) x>43/6

OpenStudy (anonymous):

just an fyi

OpenStudy (anonymous):

what is the solution for it though

OpenStudy (anonymous):

jim, dont divide by 8

jimthompson5910 (jim_thompson5910):

on which step?

OpenStudy (anonymous):

{xIx__}

OpenStudy (anonymous):

4

jimthompson5910 (jim_thompson5910):

I multiplied both sides by 8 in that step

OpenStudy (anonymous):

u should eliminate the 3 first, fyi, not subtract the second 3

OpenStudy (anonymous):

oh, my bad

jimthompson5910 (jim_thompson5910):

I'm assuming the problem is \[\frac{3}{8}(5+6x)+3>21\] right?

OpenStudy (anonymous):

so would the answer be; {xIx>129/18}

jimthompson5910 (jim_thompson5910):

If the problem is \[\frac{3}{8}(5+6x)+3>21\], then \[x > \frac{43}{6}\]

jimthompson5910 (jim_thompson5910):

You can reduce stew

OpenStudy (anonymous):

i got x>20/48 i think its wrong tho

OpenStudy (anonymous):

How do you reduce it?

jimthompson5910 (jim_thompson5910):

divide both numerator and denominator by 3 to reduce

OpenStudy (anonymous):

u cant divide 43 by 3

OpenStudy (anonymous):

no, but you can reduce 129 by 3

OpenStudy (anonymous):

where do u see 129?

jimthompson5910 (jim_thompson5910):

43 = 129/3

jimthompson5910 (jim_thompson5910):

it's what stew originally got

OpenStudy (anonymous):

oh my bad :D

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