Mathematics
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OpenStudy (anonymous):
3/8(5+6x)+3>21
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OpenStudy (anonymous):
\[\frac{3}{8(5+6x)+3}>21\]
this ?
OpenStudy (anonymous):
subtract 3
multiply by 8/3
subtract 5
divide by 6
OpenStudy (anonymous):
@imran i am guessing it is
\[\frac{3}{8}(6+5x)+3=21\]
OpenStudy (anonymous):
ok, that's probably more likely
OpenStudy (anonymous):
either way is correct
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jimthompson5910 (jim_thompson5910):
3/8(5+6x)+3>21
3/8(5+6x)>21-3
3/8(5+6x)>18
3(5+6x)>144
15+18x>144
18x>144-15
18x>129
x>(129)/(18)
x>43/6
OpenStudy (anonymous):
just an fyi
OpenStudy (anonymous):
what is the solution for it though
OpenStudy (anonymous):
jim, dont divide by 8
jimthompson5910 (jim_thompson5910):
on which step?
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OpenStudy (anonymous):
{xIx__}
OpenStudy (anonymous):
4
jimthompson5910 (jim_thompson5910):
I multiplied both sides by 8 in that step
OpenStudy (anonymous):
u should eliminate the 3 first, fyi, not subtract the second 3
OpenStudy (anonymous):
oh, my bad
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jimthompson5910 (jim_thompson5910):
I'm assuming the problem is \[\frac{3}{8}(5+6x)+3>21\] right?
OpenStudy (anonymous):
so would the answer be; {xIx>129/18}
jimthompson5910 (jim_thompson5910):
If the problem is \[\frac{3}{8}(5+6x)+3>21\], then \[x > \frac{43}{6}\]
jimthompson5910 (jim_thompson5910):
You can reduce stew
OpenStudy (anonymous):
i got x>20/48
i think its wrong tho
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OpenStudy (anonymous):
How do you reduce it?
jimthompson5910 (jim_thompson5910):
divide both numerator and denominator by 3 to reduce
OpenStudy (anonymous):
u cant divide 43 by 3
OpenStudy (anonymous):
no, but you can reduce 129 by 3
OpenStudy (anonymous):
where do u see 129?
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jimthompson5910 (jim_thompson5910):
43 = 129/3
jimthompson5910 (jim_thompson5910):
it's what stew originally got
OpenStudy (anonymous):
oh
my bad :D