how do you find intercepts from standard form?
You could change it into slope intercept, or you could use the equation -b/a
no,but there's like a legit, lke, thing u can do, and i forget it. poop on a flea
like*
Actually, it's -a/b
For Ax+By=C, the intercept is found by -A/B
no, thats slope
Oh im sorry, I don't know why I wrote that....
lolz, i forgive you
x-int is C/-A
according to who..?
According to me.
mmk
Oops. y-int is C/-B
I keep forgetting the negative sign....
-_-
then wat's -1/1?
FINAL ANSWER: X-Int: -C/A Y-int: -C/B
*sigh*
to find y intercept set x=0 and solve for y vice versa for x intercept
If A is nonzero, then the x-intercept, that is, the x-coordinate of the point where the graph crosses the x-axis (where, y is zero), is −C/A. If B is nonzero, then the y-intercept, that is the y-coordinate of the point where the graph crosses the y-axis (where x is zero), is −C/B, and the slope of the line is −A/B.
thank you phi. chess machine, thats the legit thing i was talking about
You said in standard form.
You wouldn't have to set anything in standard form, the answer is right there....
yeah. thats using standard form Ax+By=C
Yes, but the intercepts are literally given to you in the equation. If it was like f(x)= 3x^3 +12x^2+3x+7, then you would have to set it equal to zero. In standard form, the equation tells you the intercepts without that, you can just look at the coefficients.
uhm, i have no idea wat u just said. sorry.
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