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Mathematics 9 Online
OpenStudy (anonymous):

how do you find intercepts from standard form?

OpenStudy (anonymous):

You could change it into slope intercept, or you could use the equation -b/a

OpenStudy (anonymous):

no,but there's like a legit, lke, thing u can do, and i forget it. poop on a flea

OpenStudy (anonymous):

like*

OpenStudy (anonymous):

Actually, it's -a/b

OpenStudy (anonymous):

For Ax+By=C, the intercept is found by -A/B

OpenStudy (anonymous):

no, thats slope

OpenStudy (anonymous):

Oh im sorry, I don't know why I wrote that....

OpenStudy (anonymous):

lolz, i forgive you

OpenStudy (anonymous):

x-int is C/-A

OpenStudy (anonymous):

according to who..?

OpenStudy (anonymous):

According to me.

OpenStudy (anonymous):

mmk

OpenStudy (anonymous):

Oops. y-int is C/-B

OpenStudy (anonymous):

I keep forgetting the negative sign....

OpenStudy (anonymous):

-_-

OpenStudy (anonymous):

then wat's -1/1?

OpenStudy (anonymous):

FINAL ANSWER: X-Int: -C/A Y-int: -C/B

OpenStudy (anonymous):

*sigh*

OpenStudy (phi):

to find y intercept set x=0 and solve for y vice versa for x intercept

OpenStudy (anonymous):

If A is nonzero, then the x-intercept, that is, the x-coordinate of the point where the graph crosses the x-axis (where, y is zero), is −C/A. If B is nonzero, then the y-intercept, that is the y-coordinate of the point where the graph crosses the y-axis (where x is zero), is −C/B, and the slope of the line is −A/B.

OpenStudy (anonymous):

thank you phi. chess machine, thats the legit thing i was talking about

OpenStudy (anonymous):

You said in standard form.

OpenStudy (anonymous):

You wouldn't have to set anything in standard form, the answer is right there....

OpenStudy (anonymous):

yeah. thats using standard form Ax+By=C

OpenStudy (anonymous):

Yes, but the intercepts are literally given to you in the equation. If it was like f(x)= 3x^3 +12x^2+3x+7, then you would have to set it equal to zero. In standard form, the equation tells you the intercepts without that, you can just look at the coefficients.

OpenStudy (anonymous):

uhm, i have no idea wat u just said. sorry.

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