Question

prove that 2cotx / (1 + cot^2 x) is equal to sin 2x

Answer 1

please. i need answers.

Answer 2

ok got it sorry it took a while

Answer 3

denominator is
\[1+\cot^2(x)\]
if you start with
\[\sin^2(x)+\cos^2(x)=1\] divide everything by
\[\sin^2(x)\] you get
\[1+\cot^2(x)=\frac{1}{\sin^2(x)}\] and so that is your denominator. therefore whole expression is
\[2\cot(x)\times \sin^2(x)\]
\[=2\frac{\cos(x)}{\sin(x)}\times \sin^2(x)\]
\[=2\cos(x)\sin(x)=\sin(2x)\]

Answer 4

thank u very much

Answer 5

yw