Question

Identify and draw the following graph:
i) 2x^2 + y^2 - 4x + 4y + 6 = 0

Completed the square, and I got:
2(x+1)^2 + (y+2)^2 = 0

I have been taught that you are not suppose to have a number in front of the bracket. With that number there, I am not sure as to how I am suppose to proceed.

Answer 1

it's a degenerate of an ellipse called a point. ellipse equation: (((x-h)^2)/a)+(((y-k)^2)/b)=r (radius). since radius = 0, it's a point.

Answer 2

((x+1)^2)+((y+2)^2)/2=0 is ur eqn.

Answer 3

point in (-1,-2)

Answer 4

OK I see it, so the "a" would be 1, and the "b" would be sqrt{2}

Answer 5

no, i just divided both sides by 2.

Answer 6

it's 1 and 2.

Answer 7

The Ellipse equation comes in the form:
(x - h)^2/a^2 + (y - k)^2/b = 1

Answer 8

(x - h)^2/a^2 + (y - k)^2/b^2 = 1

Answer 9

so wouldn't the "b" value be \sqrt{2}?

Answer 10

oh yes, i'm sorry :)

Answer 11

How does this actually look like?

Answer 12

I don't know how to go about with graphing it..

Answer 13

Still confused about this question. Would someone mind helping me?