Question

solve f(x)=x^2-2x-4...find the vertex, line of symmetry and the min/max of f(x)

Answer 1

ah vertex!
use
\[x=-\frac{b}{2a}\]

Answer 2

in this case
\[a=1,b=-2,-\frac{b}{2a}=1\]

Answer 3

first coordinate of the vertex is 1, second is
\[f(1)=1-2-4=-5\] so it is
\[(1,-5)\]

Answer 4

since this is a parabola that opens up, -5 is the minimum (think of the picture)

Answer 5

ok so that's the equation I use to find the vertex...whew! thanks cause I forgot! lol

Answer 6

yeah easy. don't let anyone try to tell you you have to
1) complete the square
2) take the derivative
3)locate the midpoint of the zeros

Answer 7

(i have seen all of the above)

Answer 8

ah! thanks so much for the tip!

Answer 9

yw