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OpenStudy (anonymous):
Factor by Grouping 6x^3 - 21x^2 + 10x-35
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jimthompson5910 (jim_thompson5910):
\[\large 6x^3-21x^2+10x-35\] \[\large (6x^3-21x^2)+(10x-35)\] \[\large 3x^2(2x-7)+5(2x-7)\] \[\large (3x^2+5)(2x-7)\] So \[\large 6x^3-21x^2+10x-35=(3x^2+5)(2x-7)\]
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