Question

log3^(1/3)

Answer 1

= (1/3)log3

Answer 2

approx 0.159

Answer 3

hold on

Answer 4

i am willing to bet that this is
\[\log_3(\frac{1}{3})\] so the answer is
\[-1\]

Answer 5

\[\large \log_{3}(\frac{1}{3})\]


\[\large \log_{3}(3^{-1})\]


\[\large -1\log_{3}(3)\]


\[\large -1(1)\]


\[\large -1\]
So \[\large \log_{3}(\frac{1}{3})=-1\]

Answer 6

because
\[3^{-1}=\frac{1}{3}\]

Answer 7

approx 0.159

Answer 8

giraffe11?

Answer 9

both answers could be right depending on what base the log is :)

Answer 10

my answer comes with a money back guarantee

Answer 11

@giraffe the idea is that
\[\log_b(x)=y\iff b^y=x\] so if you see
\[\log_3(\frac{1}{3})=y\] you try to fill in the spot
\[3^x=\frac{1}{3}\]

Answer 12

should have written
\[3^y=\frac{1}{3}\] to be less confusing.
if that exponent is clear, then you are in good shape.
if you are shaky with exponential notation it is easy enough to cheat with a calculator

Answer 13

thanks