Question

if log (ab) base is a = x
then log(ab) base is b = ?

Answer 1

help me any1

Answer 2

im a little confused, is this the question?

\[\log_a(ab) = x \Rightarrow \log_b(ab) = ?\]

Answer 3

yes

Answer 4

so with:
\[\log_a(ab)\]we can split it since there is multiplication on the inside:
\[\log_a(ab) = \log_a(a)+\log_a(b) = 1+\log_a(b) = x \iff \log_a(b) = x-1\]

Answer 5

hmn , yes but then ?

Answer 6

1/x-1 +1

Answer 7

now looking at:
\[\log_b(ab)\]we obtain:
\[\log_b(ab) = \log_b(a)+\log_b(b) = \log_b(a)+1\]
we now need a way to deal with:
\[\log_b(a)\]that turns out to be:
\[\log_b(a) = \frac{1}{\log_a(b)} = \frac{1}{x-1}\]
so the final answer is:
\[\log_b(ab) = \frac{1}{x-1}+1\]

Answer 8

thanks very much please wait i am posting another question

Answer 9

http://openstudy.com/groups/mathematics/updates/4e51e2fd0b8b958804b28d1e#/groups/mathematics/updates/4e51e3980b8b958804b28e91

Answer 10

yes thanks very much

Answer 11

to whom