The cubic polynomial f(x) is such that the coefficient of x^3 is 1 and the roots of f(x) = 0 are 1, k and k^2. It is given that f(x) has a remainder of 7 when divided by x-2

(i) Show that k^3 - 2k^2 - 2k - 3 = 0
(ii) hence find a value for k and show that there are no real values of k which satisfy this equation

I really don't understand this q @@ help

Question

The cubic polynomial f(x) is such that the coefficient of x^3 is 1 and the roots of f(x) = 0 are 1, k and k^2. It is given that f(x) has a remainder of 7 when divided by x-2

(i) Show that k^3 - 2k^2 - 2k - 3 = 0
(ii) hence find a value for k and show that there are no real values of k which satisfy this equation

I really don't understand this q @@ help

anonymous · Answer

:D I cheated off my friend for (i). lol. cheating makes me understand?

anonymous · Answer

lol, if you understand, in the end it doesnt matter.

anonymous · Answer

<3 Joeeeeeeeee~! :D