Find how many ways the letters of the word DECISIONS can be arranged so that the N is somewhere to the right of D
Assume that n and d are just one letter, there are 2s 2i and 1e 1c 1o So there are 8elements, so it can be arrenged 8! Times and also n and d can arrenge 2! Times so the answer is 8!*2!
hmmm i think this may be hard
because it says "somewhere" to the right.
well the answer is 45360
really thought provocking
Oops you re right
I answered when they bear to each other
i should probably thingFind how many ways the letters of the word DECISIONS can be arranged so that the N is somewhere to the right of D before i type, but maybe you have to break it up into cases. if the D is first then there are 7! ways if D is second there are 6 times 6! ways if D third there are 6*5 *5! ways etc
Try keeping D constant at each positions and N at any position right to it and permutating remaninig . but the possibility of I coming right and left to D should also be considered
what the heck?? that is not what i typed. if D is first: 7! ways if D is second: 6*6! ways if D is third 6*5*5! ways etc stop me if this is nonsense
But now its easier, Now there are 7different letter and They can arrenged 9!/2!*2! There is n is to the right of d or left or d same 2sitituations So we gonna divided by 2 Finally the answer is=
45360
This one is right i think?
@bkalkan very nice!
:) thanks
Thank you:)
"pure reason" is so much nicer than counting
Join our real-time social learning platform and learn together with your friends!