Question

\[2 \int \int y(t)dtdt+\int y(t) \, dt=\sin (x)\]

Answer 1

where does the x come from? should it be sin(t)
are you supposed to find y(t)

Answer 2

sorry,
\[2 \int \int y(t)dtdt+\int y(t) \, dt=\sin (t)\]

Answer 3

Where are there two dts?

Answer 4

Err why rather.

Answer 5

I mean I suppose it's fine to double integrate, but I've never seen that before..

Answer 6

im guessing its like the inverse of the 2nd derivative
let u(t) by the result, then u'' = y(t)

Answer 7

double integral with same variable , I believe

Answer 8

Or sorry rather you're saying that u'(t) + 2u(t) = sin(t)

where u''(t) = y(t)

Answer 9

yeah

Answer 10

So solve the differential for u(t), then differentiate it twice to find y?

Answer 11

Ok, so it's just linear differential from here

Answer 12

Yep

Answer 13

Thank you much to both of you