Question

Help :/

Answer 1

hold on, let me enter the equation.

Answer 2

\[10a ^{3}b ^{2}c ^{7}/5a ^{5}bc ^{7}\]

Answer 3

all exponents must be positive.

Answer 4

2b/(a^3)

Answer 5

how did you get that?

Answer 6

sorry, 2b(a^2)

Answer 7

i mean 2b/(a^2)

Answer 8

i dont understand :/ how do the exponents come out positive?

Answer 9

You subtract the exponents in the denominators from the exponents in the numerator.

Answer 10

If the exponent is negative, you move the factor to the denominator and make it positive.

Answer 11

use exponent laws

Answer 12

wait I dont quite get that. If it's negative I do the reciprocal?

Answer 13

\[a ^{m-n} = a ^{m} / a ^{n}\]

Answer 14

yeah u do reciprocal since its negative

Answer 15

\[10a ^{3}b ^{2}c ^{7}\over 5a ^{5}bc ^{7}\]\[= \frac{10}{5}(a^{3-5}b^{2-1}c^{7-7})\]\[=2(a^{-2}b^1c^0)\]\[=\frac{2b}{a^2}\]

Answer 16

i think I get it! and if there's no exponent to a variable, it's automatically 1?

Answer 17

Right!

Answer 18

Because you did b^2-1

Answer 19

but b in the denominator had no exponent

Answer 20

yep, and anything with a 0 exponent just goes away (becomes 1)

Answer 21

but b in the denominator had no exponent

Answer 22

okay! Thanks!!