Question

precalc: Find the vertices of the hyperbola with equation: ((x+2)^2/4) - ((y+1)^2/16) = 1

Answer 1

click on "properties"
http://www.wolframalpha.com/input/?i=%28%28x%2B2%29^2%2F4%29+-+%28%28y%2B1%29^2%2F16%29+%3D+1

Answer 2

still dont understand what the vertices are....

Answer 3

oh sorry

Answer 4

center is at
\[(-2,-1)\]

Answer 5

since you have
\[\frac{(x+2)^2}{4}\] and
\[\sqrt{4}=2\]
they are two units to the right and left of the center. hence they are at
\[(-4,-1),(0,-1)\]