Mathematics
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OpenStudy (anonymous):
simplfy rational algebraic expression -6/x+sqrt7
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OpenStudy (anonymous):
\[x \sqrt{7} - 6\]
OpenStudy (anonymous):
Cookies pr0x
OpenStudy (anonymous):
?
OpenStudy (anonymous):
you sure its not -6+x sqrt7/x?
OpenStudy (anonymous):
\[\frac{-6}{x+\sqrt{7}}\]
\[=\frac{-6}{x+\sqrt{7}}\times \frac{x-\sqrt{7}}{x-\sqrt{7}}\]
\[=\frac{-6(x-\sqrt{7}}{x^2-7})\]
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OpenStudy (anonymous):
or 6 (sqrt7-x)/x^2-7?
OpenStudy (anonymous):
\[-6/x +\sqrt{7}\]
^This?
OpenStudy (anonymous):
i mean the other one..
OpenStudy (anonymous):
Oh.
OpenStudy (anonymous):
i am willing to bet it is the one i wrote
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OpenStudy (anonymous):
ok same ans...thanks i just one to be sure..
OpenStudy (anonymous):
i really dont knw whats the right solution..or procedure..ty again
OpenStudy (anonymous):
\[\frac{(n+1)!}{n!}=n\] is a start
OpenStudy (anonymous):
thanks again...
OpenStudy (anonymous):
forget about the numbers for a minute
\[n!=n\times (n-1)\times (n-2)\times ...\times 2\] and
\[(n+1)!=(n+1)\times n\times (n-1)\times ...\times 2\]
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OpenStudy (anonymous):
so
\[\frac{(n+1)!}{n!}\] leads to a whole raft of cancelation, leaving only
\[n+1\]
OpenStudy (anonymous):
so all you are left with in your problem is
\[\frac{3(n+1)}{5}\]
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
so the ans is x-5/25x^-5?
OpenStudy (anonymous):
@edemsam yes that is it
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OpenStudy (anonymous):
ok thanks again..
OpenStudy (anonymous):
but in other site the ans.is 150x^4-30x^2+sqrt(5)(5)/5x^2-1...but they didnt show the steps..