Question

\[2+3i \div-1-4i\]
simplified

Answer 1

\[\frac{2+3i}{-1-4i}\] gimmick is to multiply top and bottom by conjugate of the denominator, which is
\[-1+4i\]

Answer 2

reason being that
\[(a+bi)(a-i)=a^2+b^2\] a nice real number with no i in it

Answer 3

so write
\[\frac{2+3i}{-1-4i}\times \frac{-1+4i}{-1+4i}\]

Answer 4

you denominator will be
\[1^2+4^2=17\] and your numerator will be whatever you get when you multiply

Answer 5

okay thanks!

Answer 6

wait would a negative or positive 14 be on the top?