use the concept of slope to find t such that three points are collinear (-3,3) (t,-1) (8,6) i really dont understand this problem...step by step anyone?
you need so make sure the slopes are the same
the slope of the line between (-3,3) and (8,6) is \[\frac{6-3}{8-(-3)}\] \[=\frac{3}{11}\]
and so you have to make sure that \[\frac{-1-3}{t-(-3)}=\frac{-4}{t+3}=\frac{3}{11}\]
you good from there?
yea and thats where i got stuck
oh ok
cross multiply to get \[-44=3(t+3)\] how about now?
yes im following
\[-44=3t+9\] \[-53=3t\] \[t=-\frac{53}{3}\]hmm looks bad let me check
yea i think thats right. i understand it way better
thans!!!
you could also find the equation for the line, then replace y by -1
equation is \[-3 x+11 y-42 = 0\]
let's see if it works
ok
\[-3x+11\times -1-42=0\] \[-3x=53\] yes it works
whew i got nervous
so i could use both ways right?
sure your choice. find the line, plug in the point or make sure the slopes match up. i think first way might be shorter because in both you still have to find the slope but in second way you also have to find the equation of the line
i mean "in the first way you still have to find the equation of the line"
oh ok thanks for your help!!
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