x2 + 4x – 12 = 0 by completing the square.
add 12 to both sides \[x^2+4x=12\] take half of 4 which is 2 and write \[(x+2)^2=12+2^2=12+4=16\] \[(x+2)^2=16\] take the square root and get \[x+2=4\] or \[x+2=-4\] so \[x=2\] or \[x=-6\]
Gracias :)
welcomas
if it didnt have = 0 would it be Ex. of a diff problem, x = 16 -4 +/- 2 sqrt3 = x + 4
? i think you lost me
Nevermind lol
k
can yu help me with this... how you would use the quadratic formula to solve x2 + 5x = –2. Why is the quadratic formula the best method to use?
it is the best method to use because if you complete the square you are going to get annoying fractions
solve \[x^2+5x+2=0\] via \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with \[a=1,b=5,c=2\]
if you see \[x^2+6x-1=0\] complete the square because half of 6 is 3
but if you see \[x^2+7x-2=0\] might as well use the formula because half of 7 is 7/2 and it will be kind of messy
i am off. good luck!
:)
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