Question

help me again any1 : \[\color{red}{\text{b^2+5>9b+12}}\]

Answer 1

\[b^2+5>9\]
this is an inequality .this is satisfied if :
1) \[b>9, b<1 \]
2) \[b=10,b=-1\]
3) \[b>8 , b<0\]

Answer 2

b^2-9b+5-12=0
b^2-9b-7=0
-----> b1=(9/2)+4sqrt(2) , b2=(9/2)-4sqrt(2)
so the solution area would be as
(-infinity,b2) U ( b1,+inifinity)

Answer 3

didnt understand raheen, what is the answer finally

Answer 4

\[(-\infty,(9/2)-4\sqrt{2}] U [(9/2)+4\sqrt{2},+\infty)\]