I need steps for this one too! PLEASE HELP! 24*log(3x)=60
Ok, this is the same deal. So lets approach it the same way. This time I'll instruct and you perform
To start we need to isolate the log(3x) factor. To do that we have to get rid of the other factor 24. So we divide both sides by 24
What do we have now?
Polpak - using the principals before I divide both sides by 24 and I end up with log 10 (3x) = 2.5
Correct!
Now we re-write the log in exponential form
then I have to put in in the format as before with the logb (a)=k I get log10 (3x)=2.5
jenn.. did you delete my response?
I had posted the complete solution..
helpingtutors - did not get your response. sorry, working it through with polpak thanks
Right, so lets write the other half of that relation: b^k = a
10^2.5=3x
the b (base) in this case is 10. our 'a' is 3x, and our k is 2.5
answer was 105.4092
That's correct jenn
Now to isolate the x, we divide by the coefficient in front (the 3)
so when I calculate it I get 316.227766/3=105.409
do I have it right?
Nicely done
Thanks! I am now understanding this very tedious process!
It will get faster =)
I appreciate the time to explain it to me! That's how I learn, step-by-step! Thanks again! I awarded you another medal!
Anytime. You're a good student to work with.
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