Question

(3(d^-1)-5)-2/(3(d^-4)-2 answer in positive exponents step by step please

Answer 1

i think i might have did something wrong

Answer 2

alright well let me check if this is what you mean

\[\frac{3d^{-1}-2}{3d^{-4}-2}\]

Answer 3

if so when you have negatives like that ou can look at it like

\[\frac{3d^4-2}{3d^1-2}\]

Answer 4

umm not exactly its like this \[3(d ^{-1})^{-5})^{-2}/(3(d ^{-4})^{-2}\]

Answer 5

sorry for the bottom part its \[(3(d ^{-4})^{-2})^{-2}\]

Answer 6

and the 3 is within the parenthesis/

Answer 7

yes

Answer 8

the top will come out to be

\[3(d^{-1*-5*-2})\] i believe as your syntax is off by a bit i beileve

Answer 9

unless that 3 is in the parenthesis n the top also

Answer 10

it is lol

Answer 11

sorry

Answer 12

\[3^{-2}d^8\]

Answer 13

i believe will be the bottom

Answer 14

no wait... ^-16

Answer 15

geez it wont let me see the problems

Answer 16

i'm getting

\[\frac{3^{-2}d^{-10}}{3^{-2}d^{-16}}\]

Answer 17

when you multiply those out

Answer 18

\[=\frac{\frac{1}{9}d^{-10}}{\frac{1}{9}d^{-16}}\]

Answer 19

1/9 will cancel

Answer 20

flip them and then subtract = d^6

Answer 21

i got 1/d6 iono if thats right

Answer 22

upload your work

Answer 23

oo i kno why its because i forgot to include that the number can be negative its just that the exponents cant be negative

Answer 24

o nvm your right i did have a mistake

Answer 25

if you upload your work i can maybe see where you got off track...

Answer 26

i canceled the -6 but i forgot to flip the negative exponents and then subtracted them which gave me another answer i went back and looked over it and saw where i had the mistake

Answer 27

ah yes , if you plan on going into calculus you will do this a lot, so i'd work more on the whole manipulation of exponents, as it will help when you get there =]

Answer 28

you can also cancel everything and it will leave you d^6 i have done this before its just that it has been awhile and i forgot everything lol and yea thanks :]